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T.W.R
16th June 2009, 18:57
A pretty concise article on Horsepower & Torque

howdamnhard asked to see it, so here it is for all :done:

howdamnhard
16th June 2009, 20:45
Cheers , thanks T.W.R. a good read.

TripleZee Dyno
17th June 2009, 11:29
I agree with the writer regarding “low end torque” “high end horsepower” and the way some road testers waffle on about “waves of torque” “massive low end torque” and other bs, especially when testing the latest offering from Harley. No offence to Harley, they actually make pretty good bikes, but considering a GSX1400 or ZZR1200 (not to mention ZX14 and Busa) all put out more “low end torque” than a 96” Harley, it says more about the testers/writers than about the bikes.
I don’t agree with his assertion that HP is what makes your bike go, accelerate etc. and “Torque does none of the above” You cant have one without the other. Even he says that.
Using a chassis dyno we measure roller speed and rear wheel torque and from those we derive HP, measure engine rpm, and derive engine torque with
T(engine)=HPx5252/rpm(engine) and this is what gets put on your graph

Rear wheel hp and engine hp are essentially the same (not withstanding transmission losses etc)
Rear wheel torque and engine torque are different, because we have a gearbox, primary etc between the engine and rear wheel.
Example
At the engine
10,000 rpm
76 HP
40 ft/lbs
4:1 reduction gearbox etc
At the rear wheel we get
76 HP
2500rpm
160 ftlbs
HP is the same but torque has increased.
And that’s why your bike accelerates better in lower gears
Why you change down when going up a hill (some of us)
Because it is rear wheel torque that actually pushes us along, determines how the bike accelerates etc.
To accelerate harder we need more rear wheel torque, increase the HP or change the gear ratio.
Not wanting to be too picky but, his idea about VE is more wrong than right, and the “torque figure for a twin……is likely to be higher due to the longer stroke” is just perpetuating a common myth that long stroke motors produce more torque because they have a “long” stroke

I guess the flowery hyperbole is a bit like chrome, sounds and looks flash but actually means sweet FA
rock on

xwhatsit
17th June 2009, 12:26
Not wanting to be too picky but, his idea about VE is more wrong than right, and the “torque figure for a twin……is likely to be higher due to the longer stroke” is just perpetuating a common myth that long stroke motors produce more torque because they have a “long” stroke
Well that's actually true. Given a motor that produces the same force within the cylinder (i.e. the force pushing down the piston is the same), the motor with a longer stroke will produce more torque. For precisely the reason illustrated with diagrams in the article -- a longer stroke means a longer distance from crank centre to crankpin; so there's a bigger leverage. We all know the longer the lever, the more torque is applied.

But the side effect of that is you need more movement to produce that torque. So the piston has to move further... means trouble getting the engine to rev higher. So develops less peak power compared to how much torque it's producing, as while you might be able to put out more torque due to more leverage on the crank, you can't put out that torque as often (because redline is lower), so the rate of work is less.

Of course what you say is true in the sense that every engine is different, so many different variables. So you're right in that just because it's a long stroke motor doesn't mean it's going to produce wads of torque... which is the usual bullshit the magazines and know-it-alls at the pub like to spout.


Good article, thanks for scanning it in TWR.

TripleZee Dyno
17th June 2009, 16:05
Well that's actually true. Given a motor that produces the same force within the cylinder (i.e. the force pushing down the piston is the same), the motor with a longer stroke will produce more torque. For precisely the reason illustrated with diagrams in the article -- a longer stroke means a longer distance from crank centre to crankpin; so there's a bigger leverage. We all know the longer the lever, the more torque is applied.

But the side effect of that is you need more movement to produce that torque. So the piston has to move further... means trouble getting the engine to rev higher. So develops less peak power compared to how much torque it's producing, as while you might be able to put out more torque due to more leverage on the crank, you can't put out that torque as often (because redline is lower), so the rate of work is less.

Of course what you say is true in the sense that every engine is different, so many different variables. So you're right in that just because it's a long stroke motor doesn't mean it's going to produce wads of torque... which is the usual bullshit the magazines and know-it-alls at the pub like to spout.

Good article, thanks for scanning it in TWR.
Well I will have to disagree with you. Its not actually true. The assumption that the downward force from the piston is the same for both long stroke and short stroke engines is wrong. For the same cylinder pressure a short stroke piston will provide more downward force. If you work it all out and you will see that the torque applied to the crank will be about the same. I am talking about 2 engines, same size, same cylinder pressure, one short stroke, one long stroke, both engines with their best rod ratio.
cheers

LBD
17th June 2009, 16:35
Well actually...conrod length plays a large part in the game...the longer the conrod, the less force wasted in sideways thrust to the cylinder wall and more downward thrust on the crank.

And if the PFP is the same in a long or short conrod engine the torque would be greater in the long rod engine than the short, if all other factors were the same...

However the longer the rods, the hevear the rods the more the rotating mass, the less rpm available the less HP could be produced...

xwhatsit
17th June 2009, 17:19
For the same cylinder pressure a short stroke piston will provide more downward force.
Could you explain that to a simpleton like me?

TripleZee Dyno
17th June 2009, 18:07
Could you explain that to a simpleton like me?
no worries
assuming 2 engines same size one long and one short stroke the short stroke engine will have a bigger piston, more surface area. eg a 100 x 63 and 79 x 101 both 500cc. The 100mm bore will have around 12 sqin, the 79 mm bore around 7.5sqin. If you had say 300psi in the cylinder the force on the pistons would be 3650 lb and 2280lb. Assume max mechanical advantage for both ie best rod ratio, and you will end up with 453 ftlbs of torque at the crank in both cases.
450 ft lbs is a peak figure, lucky if it lasts more than 10-15 degrees of the power stroke so once you average it out over 720 degrees its a heap less.
cheers

Fooman
17th June 2009, 18:25
no worries
assuming 2 engines same size one long and one short stroke the short stroke engine will have a bigger piston, more surface area. eg a 100 x 63 and 79 x 101 both 500cc. The 100mm bore will have around 12 sqin, the 79 mm bore around 7.5sqin. If you had say 300psi in the cylinder the force on the pistons would be 3650 lb and 2280lb. Assume max mechanical advantage for both ie best rod ratio, and you will end up with 453 ftlbs of torque at the crank in both cases.
450 ft lbs is a peak figure, lucky if it lasts more than 10-15 degrees of the power stroke so once you average it out over 720 degrees its a heap less.
cheers

And this is the same reason twins have more torque than 4's of the same capacity - the pistons and/or the stroke are larger, leading to a higher torque. But, as they are larger, both piston speeds (related to stroke) and reciprocating masses (piston size) are larger, limiting engine speed, and therefore the maximum rate of work (i.e. power).

Cheers,
FM

Fooman
17th June 2009, 18:33
You cant have one without the other. Even he says that.


And he would be wrong!

On a purely fundamental approach, you can have power without torque, just not rotational/shaft power - reaction motors (e.g. rockets) have power, based on the purely linear thrust, and the velocity at which that thrust is developed (power = force times velocity as well as torque times rotational velocity).

Cheers,
FM

johan
17th June 2009, 18:54
And this is the same reason twins have more torque than 4's of the same capacity - the pistons and/or the stroke are larger, leading to a higher torque. But, as they are larger, both piston speeds (related to stroke) and reciprocating masses (piston size) are larger, limiting engine speed, and therefore the maximum rate of work (i.e. power).

Cheers,
FM

I don't think a twin has more torque than an IL4 with the same displacement.
Triples last posts sort of proved that, but math is not my strong side.

Please correct me if I'm wrong.

Good posts, cheers!

TripleZee Dyno
17th June 2009, 18:56
Well actually...conrod length plays a large part in the game...the longer the conrod, the less force wasted in sideways thrust to the cylinder wall and more downward thrust on the crank.

And if the PFP is the same in a long or short conrod engine the torque would be greater in the long rod engine than the short, if all other factors were the same...

However the longer the rods, the hevear the rods the more the rotating mass, the less rpm available the less HP could be produced...

Rod length does have an important role to play and rod length or lack of it is why long stroke motors can put out “low rpm torque” From a practical manufacturing point of view long stroke motors are built with relatively low rod ratios, ie short rods. The advantage of a short rod is the mechanical advantage (piston to crankpin) happens earlier in the stroke, eg a 103” HD stroker has a rod ratio of 1.2:1 and maximum mechanical advantage occurs at 67 deg ATDC so more pressure is turned into useful work. The disadvantage is friction and because frictional losses rise exponentially with rpm it doesn’t take long before the losses overtake the gains.
Having said that a 103”dragbike I worked on many years ago turned 7000rpm.
The big advantage the short stroke motor has is it can have a high rod ratio, ie long rods. Maximum mechanical advantage occurs at say 85 deg ATDC but as soon as you have a few revs going the lower frictional losses are more of a bonus than the mechanical advantage of a short rod. Lower avg piston speeds mean less power robbing inertia, means make them lighter means more revs means more power.etc etc
Its all a big trade off. Short rods accelerate the piston to and from TDC which helps with cylinder filling. Long rods "dwell" the piston at TDC which helps with the power stroke. A lot of it is to do with manufacturing techniques and materials as to what they can do or not do.
cheers

TripleZee Dyno
17th June 2009, 19:03
And he would be wrong!

On a purely fundamental approach, you can have power without torque, just not rotational/shaft power - reaction motors (e.g. rockets) have power, based on the purely linear thrust, and the velocity at which that thrust is developed (power = force times velocity as well as torque times rotational velocity).

Cheers,
FM
Thanks, that will save a lot of confusion if we get onto rocket powered powered bikes!!

xwhatsit
17th June 2009, 19:37
no worries
assuming 2 engines same size one long and one short stroke the short stroke engine will have a bigger piston, more surface area. eg a 100 x 63 and 79 x 101 both 500cc. The 100mm bore will have around 12 sqin, the 79 mm bore around 7.5sqin. If you had say 300psi in the cylinder the force on the pistons would be 3650 lb and 2280lb. Assume max mechanical advantage for both ie best rod ratio, and you will end up with 453 ftlbs of torque at the crank in both cases.
450 ft lbs is a peak figure, lucky if it lasts more than 10-15 degrees of the power stroke so once you average it out over 720 degrees its a heap less.
cheers
Ahhh right I see where you're coming from.

The way I was talking about it is where you have the same bore, same cylinder pressure. Just longer stroke. In which case you would have more torque -- not because of higher capacity causing more fuel/air being squashed and burned, but simply because there is a longer `lever' acting on the crank centre.

So we were both talking about the same thing except I didn't explain myself clearly :shutup:

In the article it says you can have torque without power -- the case cited is where you apply torque to a stuck/rusted bolt and it doesn't come undone (no work is done, nothing moves -- nonetheless you are applying torque).

TripleZee Dyno
17th June 2009, 19:46
And this is the same reason twins have more torque than 4's of the same capacity - the pistons and/or the stroke are larger, leading to a higher torque. But, as they are larger, both piston speeds (related to stroke) and reciprocating masses (piston size) are larger, limiting engine speed, and therefore the maximum rate of work (i.e. power).

Cheers,
FM
the individual cylinders of the twin would produce twice the tq compared to the individual cylinders of the 4 basically because they are twice as big, but the 4 has twice as many tq 'pulses' so overall they will end up the same.
As you say piston speeds etc affect the twin more when it comes to revs. So the tuning will be optimised to suit the operating range and intended purpose of the engine.
cheers

TripleZee Dyno
17th June 2009, 19:56
Ahhh right I see where you're coming from.

The way I was talking about it is where you have the same bore, same cylinder pressure. Just longer stroke. In which case you would have more torque -- not because of higher capacity causing more fuel/air being squashed and burned, but simply because there is a longer `lever' acting on the crank centre.

So we were both talking about the same thing except I didn't explain myself clearly :shutup:

In the article it says you can have torque without power -- the case cited is where you apply torque to a stuck/rusted bolt and it doesn't come undone (no work is done, nothing moves -- nonetheless you are applying torque).
Thats right, if you increase the stroke you will increase the torque because you have the same pressure on a longer arm. By the same token an increase in bore will give the same result because you have more pressure on the same arm.
It will work out the same, more or less
cheers

LBD
18th June 2009, 00:33
. Long rods "dwell" the piston at TDC which helps with the power stroke. A lot of it is to do with manufacturing techniques and materials as to what they can do or not do.
cheers

Short rods dwell longer at the top and bottom .....

jonbuoy
18th June 2009, 06:30
So why do Vtwins FEEL like they have more torque? I know the dyno graphs tell a different story, is it the sound or related to the longer power pulse?

TripleZee Dyno
18th June 2009, 08:25
So why do Vtwins FEEL like they have more torque? I know the dyno graphs tell a different story, is it the sound or related to the longer power pulse?
Who knows? It probably has just as much to do with what they feel like, the sound, as well as the way they are tuned.a 450 deg gap in its power pulses compared to 180 is quite big. So the Vtwin will feel different and also the way the power is transferred is different. The difference between the 120 deg and 180 deg 3 cylinder Laverdas was noticeable, but I don’t think there was any significant power difference. Big cruiser vtwins tend to be up around 80-90% of their peak tq as low as 2500 rpm, maintain it for about 2-3000 rpm and the tail off fairly quickly. Big fours may start out at around 50-60% at the same revs but usually have a rising tq curve which peaks up around half the rev range and then slowly tails off for the rest of the rpm. Performance V twins usually have less peak tq than their cruiser brothers, but a better spread and at higher rpm. Eg the difference between a Vstrom and a TL1000. Ducatis have a flat tq curve, for probably 80% of the rev range they have at least 80% peak tq. Buells and Sporty tq curves follow each other for the first 4000 rpm, then the sporty tails off and the buell rises. And that is entirely down to tuning and setup. Bore, stroke, rod ratios etc have nothing to do with it because they are exactly the same. Same for the TL and Vstrom.
All engines are tuned to operate over their intended rev range and generally speaking a twin has a smaller rev range than a 4 so thats how it gets tuned.
The Rocket 3 would have more tq than any vtwin but it I dont know if it feels like it.

TripleZee Dyno
18th June 2009, 08:29
Short rods dwell longer at the top and bottom .....
Long rods dwell longer at the TDC and short rods dwell longer at BDC (at least they used to 20 yrs ago. maybe technology has moved on a bit more than I thought)

T.W.R
18th June 2009, 14:03
Someone say rods :blink:

TripleZee Dyno
19th June 2009, 08:32
Someone say rods :blink:
This article makes more sense than the first one. Although I doubt the long rods contributed all that much to the 44% increase in power on the V8. The engine must have been in a shocking state of tune before they started.
Long rods aren't magic by themselves, they are part of the whole package and hopefully everything works together to produce an excellent result. Sum of the parts etc
cheers