This will blow your mind....

[Her_C4]

**THIS ONE WILL BLOW YOUR MIND!***

Can you figure out how this works?

*1) Go to the link below. After following the instructions in each window, click on the boy in the lower right corner of the picture.*

*2) In the last window just type in your answer in the white box using the Keyboard (there is NO cursor).*

*3) Watch the paper in the boy's hand. You will be amazed. And no, I don't know how it's done.*



Click here: Fido Puzzle (http://digicc.com/fido/)

[EJK]

Quite cool lol

[HTFU]

pretty cool. I did it a few times put in 1434 jumbled it to 3441 = 1007 , circled 1 and it didn't get it said I picked 2. Might have been the zeros.

[Headbanger]

weird.

I picked 666, and it got it right.

I no like.

This stinks of the Devil.:Punk:

[Maha]

Yeah he was right....:mad:

[Mrs Cowboyz]

very cool...now I will have to try and figure out how it did it....I'm like that!!

[tide]

pretty cool. I did it a few times put in 1434 jumbled it to 3441 = 1007 , circled 1 and it didn't get it said I picked 2. Might have been the zeros.
your maths sucks 1434 jumbled it to 3441 = 2007 not 1007 :whistle:

[Meekey_Mouse]

Lol, it didn't get it right.

I started with 0737 jumbled to 3770 subdivided to 3047 then circled 7. He came up with 2 :wacko:

[Nasty]

Yup he got it wrong ... I circled 4 and he said 3!

[Colapop]

No fair!! My mind didn't get blown... or any other part of me... :angry2:

[caesius]

Simple math. It's a variant on the old primary school trick but on a larger scale. I'm doing the paperwork now...

[jrandom]

Mmm, fun with numbers.

Each potential four-digit number with at least two different digits in it (numbers with all the same digits, subtracted from themselves, will always be zero) has a particular set of other digits that it can be changed into via the "scramble and subtract" method on that page.

Each set of output digits is unique inasmuch as three particular digits will always correspond to a given fourth.

All you have to do is tediously work out the 220-entry list of each possible three-digit combination and its associated fourth output digit, and you're away laughing. Fortunately, that sort of thing is what computers are good at.

Until the middle of the twentieth century, number theory was, unlike the likes of algebra and calculus, considered 'pure math', not of any real use.

Then, after Galois fields and combinatorial analysis won (depending on who you ask) World War II, people started taking notice.

Now you couldn't do your internet banking without it.

[Sanx]

Got mine wrong too...

[jrandom]

I started with 0737 jumbled to 3770 subdivided to 3047 then circled 7. He came up with 2 :wacko:

Did you misread the instructions? You're supposed to subtract the scrambled number from your original number. In your case, 737 - 3770 = -3033. Or the other way round, doesn't matter, will just reverse the sign of the result.

Nonsense input will generate nonsense output.

[Headbanger]

The explanation.

http://britton.disted.camosun.bc.ca/jbfido.htm

Math is evil.

[jrandom]

The explanation.

http://britton.disted.camosun.bc.ca/jbfido.htm

Math is evil.

Cool!

Trust me to take an overly complicated stab at it.

[Mrs Cowboyz]

Your explanation wasnt too complicated jrandom.... For those that reckoned it got it wrong would you mind posting your original number up and the jumbled as well?

[nadroj]

Yup he got it wrong ... I circled 4 and he said 3!

Blonde....

[Mikkel]

That's really clever. I can remember how we were taught rules to determine if something was evenly divisible by all numbers ranging from 1 (doh) to 9.
Interesting how the cross-sum rule can be used here...


Any integer can be expressed as X=A*9+B, B being an interger between 0 and 9. If two numbers have an identical cross-sum(i.e. have the same numbers in them) they'll belong to the system described by one given B. If you take the difference between such numbers they will indeed always be evenly divisible by 9 since: Y=X2-X1=(A2*9+B2)-(A1*9+B1)=(A2-A1)*9, since B1=B2...
Apply the same rules to the taking one number out and remember that the cross-sum has to be 9 if the interger is to belong to the series of numbers given by X=A*9.