Could a "heavy" racer win?

[gixerracer]

If it is then I am morbidly obese, not quite as heavy as that fat cunt Shirrifs though

Hahaha not as fast either

[Moooools]

Easy big fulla, take off the cranky pants and put on something a lil' more comfortable.

How are people are supposed to read " a heavy rider and a light rider given infinite horsepower and braking power, would reach the limits of their tires at the same point." out of you're post? And when I can find a bike with "infinite horsepower and braking power" I might actually come back and revisit your argument....

Until then I'll content myself with the fact that mass has to be accelerated and decelerated in a straight line as well as centripetally. So given a difference in mass there has to be a difference in force (Force =Mass x Acceleration).

We're also trying to exert this force to travel a set distance in the shortest amount of time, right? Which equals Work. Work = (Force x Distance)/Time? And what is the unit of Work? Horsepower. Therefore for 2 riders of different weight to travel the same distance in the same time the heavier rider must use more horsepower (work done by engine, brakes, tyres). But if we're talking equally talented riders on equal bikes performing the same work, the heavier rider must take longer.

This is very simplistic, but it's how it sits ok in my head.

I will have you know I am wearing my fat pants from the warehouse. And they are exceedingly comfortable.

The 'infinite power and and braking' part was just to clarify exactly what I meant. I implied that it was not taking into account these two factors but maybe that was a bit subtle. Saying that they are infinite just makes it abundantly clear what I mean.

The term you re looking for is not 'work' it is 'power'. Work refers to energy not power. The equation is right however, and your following statement is true. But that was not the point of my post. The post was simply talking about grip. Just grip. Only grip. Nothing but grip. Something other than grip? No nothing else.

Understood?

[Robert Taylor]

Dont ever beleive anything that cunt tells you

Aside from the fact Im a good c..t and you are going to win more races

[crazy man]

Dont ever beleive anything that cunt tells you

l dont!!! he never gets your bike set up right! you are better of with a dead chinese to work on it lol

[Robert Taylor]

l dont!!! he never gets your bike set up right! you are better of with a dead chinese to work on it lol

And you are?

BTW 5 current NZ champions and a number of those who defected from that tyre changing guy and teller of ripping yarns might just disagree with your humorous statement

[CHOPPA]

Aside from the fact Im a good c..t and you are going to win more races

Thats just blown ya credibility RT! haha

[crazy man]

And you are?

BTW 5 current NZ champions and a number of those who defected from that tyre changing guy and teller of ripping yarns might just disagree with your humorous statement

looks like l will have to put you in the cooking pot for that

[Shaun]

looks like l will have to put you in the cooking pot for that

You look so much like Glen williams the ugly one your av that is

[codgyoleracer]

You look so much like Glen williams the ugly one your av that is

As i said to him before, "He's so ugly that even dogs close there eyes when they are dry humping his leg".

[Shaun]

As i said to him before, "He's so ugly that even dogs close there eyes when they are dry humping his leg".

Like ya style RED

[crazy man]

As i said to him before, "He's so ugly that even dogs close there eyes when they are dry humping his leg".

please dont talk to your self lmao

[codgyoleracer]

please dont talk to your self lmao

I think you are confusing me with your best mate G.H

[crazy man]

I think you are confusing me with your best mate G.H

bugger l stuffed up sorry

[Dave-]

So I've skim read over this thread, I'm pretty sure I get what everyone is saying (or trying to say)

here's how I see it.

the taller, lighter rider has the cornering advantage, by modeling a motorcyclist as a mass rotating around a parallel axis (using parallel axis theorm) the rider who's mass is closest to the axis with the lowest weight will have the lower tangential force which means the corner can be completed at a greater angular velocity.

in a straight line here's how I see it.

we know there is a static force of friction, that is the absolute force that the tyre will not slip at, any more and it begins slipping and becomes the kinetic force of friction, the equation is F.s = u * N (where I'm missing a load of sub script and a greek letter).

we also know the tyre excerts a torque and a tangential force is found as T = I * w (where I'm missing another 2 greek letters) and the tangential force will be divided by the radius.

so we can find the force at which a tyre will slip given the radius and mass and angular acceleration of the tyre and the weight of bike (assuming it has no front wheel, divide by the mass distribution) and coefficient of friction of a given tyre by saying:

(I * w)/r = u * N and solve for whatever dependant variable you wish, input the rest.

and because a wheel is an odd shape you'll have to do some pretty strange maths to work out the moment of intertia (yay torsional oscilations!) but that's beside the point.

what you really need to do next is solve the equation for angular acceleration and find the limit as mass tends to infinity.

I'm pretty sure I'm right, I'll ask my lab tutor in about a weeks time.

[Kickaha]

we know there is a static force of friction, that is the absolute force that the tyre will not slip at, any more and it begins slipping and becomes the kinetic force of friction, the equation is F.s = u * N (where I'm missing a load of sub script and a greek letter).

we also know the tyre excerts a torque and a tangential force is found as T = I * w (where I'm missing another 2 greek letters) and the tangential force will be divided by the radius.

so we can find the force at which a tyre will slip given the radius and mass and angular acceleration of the tyre and the weight of bike (assuming it has no front wheel, divide by the mass distribution) and coefficient of friction of a given tyre by saying:

(I * w)/r = u * N and solve for whatever dependant variable you wish, input the rest.

and because a wheel is an odd shape you'll have to do some pretty strange maths to work out the moment of intertia (yay torsional oscilations!) but that's beside the point.

what you really need to do next is solve the equation for angular acceleration and find the limit as mass tends to infinity.

Quick everybody run and hide the University educated have arrived to baffle us with bullshit no one in the real world cares about