That's absolutely true. I haven't been measuring all possible variables.
I did a spot of reading after your comment. Yep, atmospheric pressure - and humidity - are big variables as well. The thing is, it's a mechanical carburettor. It doesn't adapt to inlet conditions the same way that ECU and sensor controlled fuel injection could do. About the best that I can hope for is that the slow air circuit can do some compensation for a few millibars up or down.
The AFR gauge lets me know what's happening with the mixture vs external conditions.
Colder weather: mixture leans a point or two
Humidity: mixture gets richer by a point or two
Atmospheric pressure: guesswork, frankly, but less of a change than might be expected. I haven't noticed any discernable changes due to weather, and the bike's never been high enough above sea level for altitude to be a serious problem.
The engine vibration leading to handlebar tingle doesn't seem to associate with the AFR readings, but it does correlate with cold headwinds pretty tightly. Warm day, smooth motor. Cold day, rough motor, and it gets worse at speed.
The thing with the temperature of the fuel bowls... I really do think that something is going on with these running too cold. There have just been too many times it's happened.
So, calculations, starting with latent heat of evaporation, petrol to air. These results are by no means definitive, they guide decisions, nothing more. It's a whole lot easier to spend a night or two running the numbers than it is to build things that don't work. I've made lots of assumptions with these:
1) 100% volumetric efficiency at all RPM
2) throttle position is irrelevant
3) perfect air-fuel ratio
4) air density is 1.2 kg / m3
5) humidity is constant and low enough to not be important
I'm not sure how to insert a table (anyone?) so here's the result for 1000 RPM.
At 1000 RPM, 900cc engine, it's doing 16.7 RPS (revolutions per second). Air volume inhaled per second is 0.015 m3. The mass of air handled is 0.018 kg, with a corresponding 1/15th mass of petrol of 1.2 grammes. These numbers scale directly with RPM, just multiply by whatever number of thou RPM the engine is being revved to.
The heat of evaporation of petrol took some working out and I really hope I got this right... I worked off this wikipedia page:
https://en.wikipedia.org/wiki/Petrol...f_vaporization
It's based on relative density, presumably relative to water, and expressed in kcal / kg. This means that in terms of power absorbed I had to link the value calculated, 265.5 kcal / kg @ 20 C, to the mass of fuel being used per second, and I had to convert calories per second to watts.
So:
1 watt = 1 joule / second
1 calorie = 4.185 joules
Again, at 1000 RPM, 1.2 g of fuel needs 0.319 kcal to evaporate, or 319 calories. The heat absorbed doing this is the number of joules per second needed, equivalent to the number of calories / 4.185.
So at 1000 RPM, at 20 C, 76 watts is needed in order to evaporate the fuel.
This number scales directly by RPM so at, say, 5000 RPM, 380 watts is needed. It sounds like a lot of energy but almost all of it will come from the intake air and a warmed-up engine.
What I haven't done yet is to run the numbers again for air at 10 C and at 30 C. I think it's worth doing. Temperature is a variable throughout most of these calculations and those two points should be enough to indicate trends.
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