MotoGP 500

**madkeenandy** · 7th September 2006, 20:40

Originally Posted by Kickaha

Knaptons bike is no faster than any of the other FXR out there though and has had his arse kicked by a few of them

DC's bike has 18hp and is a lot lighter

yer, but he put a different pipe on it and tuned the carb a little bit since last meeting.

**Buddha#81:Me** · 7th September 2006, 20:53

Originally Posted by madkeenandy

Nah Peter Knapton was taking his out, dad wanted to compare them.

Just got back, the standard FXR has the grand amount of 13.5 HP

While Peter's has 15

and has huge amounts of talk starting way before dad's in the rev range, and the little line stays up there when the line for the standard FXR drops (after 10,500 rpm to redline)

It'll be interesting to see how it goes at BOB, i doubt it'll keep up with DC tho.

Id rather be on an FXR for 55 mins than fighting DC's MB, but I am a fat lazy ficker.
Look out all............ my f5 weapon is completed and ready to go.

**Buddha#81:Me** · 7th September 2006, 20:57

Originally Posted by madkeenandy

yer, but he put a different pipe on it and tuned the carb a little bit since last meeting.

Will this be the first FXR to lunch itself in the quest of HP.

**Kickaha** · 7th September 2006, 21:02

Originally Posted by gav

(Daniel Jansen, you'd know him Kick?)

I know of him, he was quite fast at one of the Greymouth Meetings

Originally Posted by spud racer

I am a fat lazy ficker.

yes,yes, that is correct you are

**madkeenandy** · 7th September 2006, 22:20

Originally Posted by spud racer

Look out all............ my f5 weapon is completed and ready to go.

What your pit bike? i thought it was 110cc... or is there something im missing here....

**F5 Dave** · 8th September 2006, 09:19

Originally Posted by spud racer

Will this be the first FXR to lunch itself in the quest of HP.

Nah Dave D up in Auckers chernobyl'd his super worked FXR months ago. They do die with too many revs.

The flat torque (talk

) curve does help on longer track as it means the bike can pull taller -thus wider spaced- gearing & be in the power for a larger time than a higher output bike, that drops off peak & has to pull itself back up again. Trust me my 50 falls into the later category. Means a wide spread power bike is faster than it should be compared to a shorter track.

Sheesh, one moment we're talking about motoGP then all of a sudden we are blithering on about buckets. Cool!

**Ivan** · 8th September 2006, 13:25

Originally Posted by F5 Dave

Well maybe the 20ish one is a restricted version & the main restriction is in the pipe that they change for other markets, which is why the Tyga pipe made so much diff. But would only be high 20s real world unrestricted.

The manufacturers dyno them to get the brochure number (probably the best of several) on an optimistic dyno & then work out how much loss occurs through the gearbox etc, usually about 22%. Erm lets check my math, = 31.2hp, so they had to find a real good one & dyno it unrestricted on an optimistic dyno.

All quite feasible, but all complete bull.

Yeah and theres Horsepower at the crankand horespower at the rear wheel and as you are saying you lose alot more throught the gearbox etc

Ill get my book from tech that explains it well

**k14** · 8th September 2006, 13:36

Originally Posted by Ivan

Yeah and theres Horsepower at the crankand horespower at the rear wheel and as you are saying you lose alot more throught the gearbox etc

Ill get my book from tech that explains it well

Yeah friction is one of those concepts thats pretty hard to understand aye

**Hillbilly** · 8th September 2006, 16:47

This might be of some help:

conversion units of power
kilogram force-Newton and Newton-kilogram force (UNI 7202-73)
1 kgf = 9.80665 kg*m/s2 = 9.80665 N - 1N = 1/9.80665 kgf = 0.101971621 kgf

calorie-joule and joule-calorie (UNI 7203-73)
1 cal = 41868 W*s = 4.1868 J - 1 J = 1 W*s = 1/41868 cal = 0.2388459 cal

cv-kilowatt e kilowatt-cv (UNI 7204-73)
1 CV = 75 kgf*m/s = 75 * 9.80665 N*m/s = 0.73549875 kW
1 kW = 1/0.73549875 CV = 1.359621617 CV

kilocalorie hour-watt e watt-kilocalorie hour (UNI 7205-73)
1 kcal/h = 4186.8/3600 W = 1.163 W - 1 W = 1/1.163 kcal/h = 0.85984523 kcal/h

1 watt = 1 joule/second.
One watt corresponds to the necessary power for lift of 1 meter a mass of 102 grams in 1 second.

1 kW = 0.7457 HP 1 HP = 1.34102 kW
1 CV = 1.01387 HP 1 HP = 0.98631 CV
1 kilogrammeter = 0.138 foot pound 1 foot pound = 7.233 kilogrammeters