Math nerds UNITE!

[Coyote]

How about 0.374373125? Real men don't need units.

Radians right?

[Jamezo]

....you want a prize?

[Brian d marge]

Sorry pished again ...can and will aswer later .. DOver is heading down the same street as you ..be careful with friction ,,there its not an exact science ,,,,

Stephen

Ps I was working in Omiya to day the crumpet was fantastic ( you should see what they are doing with Hotpants and stockings !!!) ,,and there is english beer on tap ,, ( and 30 year old single malt is friggen cheap ,,made in Islay by a fella called goalag or gonad ....)

sober I can be of more help

[The Pastor]

ok math nerds time to shine yet again.

How the flipping jenkins do you convert liters per day to meters per second??

And also kg/s to m/s?

Any help would be awesome.

Rm

[Whynot]

ok math nerds time to shine yet again.

How the flipping jenkins do you convert liters per day to meters per second??

And also kg/s to m/s?

Any help would be awesome.

Rm

try using this

edit: hang on .... kg/s to m/s
thats mass flow to linear velocity ... ?
you will need to know the density of whatever it is you are measuring to start with ...

liters/day to meters/sec - volume to distance effectively
you will need to specify the size of the pipe/tube/drain or whatever the liquid? is having its speed being measured in

[Whynot]

this should help out a bit

http://www.lerc.nasa.gov/WWW/K-12/airplane/mflow.html

[k14]

ok math nerds time to shine yet again.

How the flipping jenkins do you convert liters per day to meters per second??

And also kg/s to m/s?

Any help would be awesome.

Rm

you sure you havent missed a little thing out there? Maybe supposed to read litres per day to cubic meters per second?

[The Pastor]

Cheers man, but that is a little hard for me to understand.

liquid density = 1170kg/m^3
pipe diameter 30cm
rate 17886070.38 liters per day.

how do I work out the velosity?

[Whynot]

basically it says that

M = r.V.A

where:
mass flow rate = M (kg/s)
density = r
velocity = v
Cross sectional area of the pipe = A

so you need to work out the cross sectional area of the pipe in metres squared.
You will also need to convert your litres per day factor into mass flow

1 litre = 0.001 m3
1 day = 86400 s
M = (kg/s)
Q = (m3/s)

M = r.Q

where M = Mass flow rate
r = density
and Q = Volume flow rate

then just chuck the numbers in and it should come out

easy

[Hitcher]

Hot bath. Bottle of Scotch. Razorblade.

[The Pastor]

basically it says that

M = r.V.A

where:
mass flow rate = M (kg/s)
density = r
velocity = v
Cross sectional area of the pipe = A

so you need to work out the cross sectional area of the pipe in metres squared.
You will also need to convert your litres per day factor into mass flow

1 litre = 0.001 m3
1 day = 86400 s
M = (kg/s)
Q = (m3/s)

M = r.Q

where M = Mass flow rate
r = density
and Q = Volume flow rate

then just chuck the numbers in and it should come out

easy

Cheers so much man would you mind checking out my working?

Given data
viscosity 6.3 x 10^-3 kg/m/s
Density 1170kg/m^3
flow rate 17886070.38 L/day
pipe diamerter 30 cm

First I got the flow rate into m^3
17886070.38*.001 = 17886.07038

then m^3 per second

17886.07038 / 86400 =0.207014703472 =M

from M/rA =V

0.207014703472/(1170(pi*(.3*.3/4) = 2.928m/s?

so V = 2.928m/s?

Or am I way off here?

[Whynot]

simplified a bit ...

V = M/(r.A)

therefore

V = r.Q/(r.A)

V = Q/A

hence velocity = volume flow rate / Area

[Whynot]

Cheers so much man would you mind checking out my working?

Given data
viscosity 6.3 x 10^-3 kg/m/s
Density 1170kg/m^3
flow rate 17886070.38 L/day
pipe diamerter 30 cm

First I got the flow rate into m^3
17886070.38*.001 = 17886.07038

then m^3 per second

17886.07038 / 86400 =0.207014703472 =M

from M/rA =V

0.207014703472/(1170(pi*(.3*.3/4) = 2.928m/s?

so V = 2.928m/s?

Or am I way off here?

yea looks ok to me ... does the answer sound right ?

[The Pastor]

yep thank heaps aye,

[Hitcher]

Presumably 30cm is the internal diameter of the pipe? Given the lack of data to the contrary, I presume that it is a perfect pipe i.e. no head loss due to friction?