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Thread: blinkers that dont flash.

  1. #1
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    13th January 2004 - 11:00
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    blinkers that dont flash.

    Heresn a screwey one for ya. On a yam 750 the indicators flash very slowly
    rev the bike up and they flash a lil bit faster.
    Thinking incorect wattage on the bulbs I checked one side and both were 23 watts. I thought alhh easy -so i fitted a 10 watt bulb into one indicator.-It made matters worse -now that just plain dont make sense.
    I also tried fitting a new solenoid -a 21 amp -and it diddnt even light the bulbs up. -Ideas guys??
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  2. #2
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    19th March 2004 - 11:00
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    Ok. Was the battery fully charged at the time?
    That happened all the time on the Honda CB125T. What you want is a battery putting out more voltage (hence the normal speed flashing when you rev and put out more voltage), or a different flasher unit.
    If both sides were flashing at equal speeds and doing the same thing, either someone has replaced all 4 bulbs incorrectly (unlikely) or it is a problem as above. Battery getting worse as you go is maybe another thing - check voltage across the battery
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  3. #3
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    13th February 2004 - 12:00
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    21-23W seems about right for indicator bulbs. as PT says, either a flat/tired battery which is making things flash slowly, or too LOW a wattage in the bulbs. From my experience with flasher units, some are tired, and even though the are rated the same as another unit, they flash at different speeds. Basic flaser units are bimetallic strips - as current flows through them they heat up, bend and lose contact, then cool and re establish contact again. Hence the lights switch on and off.
    What you are more likely to have is a relay with a capacitor and solenoid in it. I assume reducing the capacitance will increase your flashing speed as the capacitor charges faster, and hence the relay will switch faster. I am not sure on that though. Must try it sometime.

  4. #4
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    13th February 2004 - 12:00
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    oh and about the lower wattage slowing things down even more:
    P=VI, power = voltage*current
    I=Q/t therefore Q = It, charge = current*time
    if you decrease the power, and keep the voltage at 12v, obviously current must decrease. As both the flasher units rely on a set amount of charge building up/passing through, a decrease in current means an increase in time taken.

    Simple really

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