Could a "heavy" racer win?

[wharfy]

Jared was at least that size, and rode bloody awsome

Stop it you guy's me being 95 kilo's is not going to be an excuse for being crap if you keep this up !
(Ginger Molloy has already fucked the being old as an excuse for being crap)

[SWERVE]

ha, looks like this guy is using the NEW TYRE Profile of 120-0-17 front 180-0 17 rear

caption:
Its ok little guy.... just stay still in there untill we get past the gate... then you can come out.
The lengths some will go to get in to a meeting free...eh

[Robert Taylor]

ummmm hasn't Nick Cole won a 600cc NZ championship?

2 alternative Nick Coles, in all respects the same but one is 110kg and the other is 90kg. 2 green Kawasakis both exactly the same except one is set up for 110kg Nick Cole and the other is set up for 90kg Nick Cole.
Who is going to lap faster?

[Latte]

2 alternative Nick Coles, in all respects the same but one is 110kg and the other is 90kg. 2 green Kawasakis both exactly the same except one is set up for 110kg Nick Cole and the other is set up for 90kg Nick Cole.
Who is going to lap faster?

The one that realises... there is no spoon.

[Moooools]

Force = Mass x Acceleration.

So, FAIL.

Unless you have found a way past the 2nd law of motion...

That's cute. But the second law of motion more closely states that the change is momentum is related to force x time.

Right now I am thinking that "Schrodingers cat" must be one of those ironic names...

If you had bothered to read all of it you may have understood. Or maybe not, perhaps there is no hope for you. I will however persevere.

Here is are the equations FOR THE CORNERING ASPECT:

F = ma
a(acceleration towards the centre of the corner) = v^2(velocity squared)/r(radius)

So if you combine the two... F(acrossways) = mv^2/r This is the force required by the tires to maintain circular motion.

The maximum corner speed is when this force is equal to the maximum force that the tires can exert without slipping. This is given by:

F(acrossways) = k(friction constant of the tyre)x F(downwards)

F(downwards) = m(mass) x g(gravity)

Sooo.... F(acrossways) = k x m x g

Now we make the two equations equal to each other.

k x m x g = mv^2/r You will notice that there is an m on each side, representing mass(of rider and bike). These can be cancelled off.

Sooo.... k x g = v^2/r

v = Squareroot(k x g x r)

The v above is the maximum speed a bike can travel around a corner without the tyre slipping. You may notice that mass is not part of the equation. Would you like to dispute that now?

If you still doubt me I can do the other two equations (acceleration and braking) for you. But this one was the most complicated so I thought I would explain it.

I am in no way saying that they will be faster or slower, just that they do not have any more or less grip.

Come at me.

[Moooools]

All riders experience the same amount of grip???? BOLLOCKS
Has nothing to do with many things listed so far comes down to what tyres they are using what compound that tyre is and what pressures they are running and also how well they bike is set up

Wake up man. I was saying that if you ignore other factors, a heavy rider does not get any more or less grip than a light rider.

[Shaun]

2 alternative Nick Coles, in all respects the same but one is 110kg and the other is 90kg. 2 green Kawasakis both exactly the same except one is set up for 110kg Nick Cole and the other is set up for 90kg Nick Cole.
Who is going to lap faster?

me in the peak of my riding and fitness hahaha 63 kg, who the fek was gunna keep up with that out of each corner on a race track

[gixerracer]

me in the peak of my riding and fitness hahaha 63 kg, who the fek was gunna keep up with that out of each corner on a race track

With the compression ratio you run you could have weighed 100kgs Dennis was only 50something kgs and even he still couldnt out gas you

[slowpoke]

That's cute. But the second law of motion more closely states that the change is momentum is related to force x time.

Right now I am thinking that "Schrodingers cat" must be one of those ironic names...

If you had bothered to read all of it you may have understood. Or maybe not, perhaps there is no hope for you. I will however persevere.

Here is are the equations FOR THE CORNERING ASPECT:

F = ma
a(acceleration towards the centre of the corner) = v^2(velocity squared)/r(radius)

So if you combine the two... F(acrossways) = mv^2/r This is the force required by the tires to maintain circular motion.

The maximum corner speed is when this force is equal to the maximum force that the tires can exert without slipping. This is given by:

F(acrossways) = k(friction constant of the tyre)x F(downwards)

F(downwards) = m(mass) x g(gravity)

Sooo.... F(acrossways) = k x m x g

Now we make the two equations equal to each other.

k x m x g = mv^2/r You will notice that there is an m on each side, representing mass(of rider and bike). These can be cancelled off.

Sooo.... k x g = v^2/r

v = Squareroot(k x g x r)

The v above is the maximum speed a bike can travel around a corner without the tyre slipping. You may notice that mass is not part of the equation. Would you like to dispute that now?

If you still doubt me I can do the other two equations (acceleration and braking) for you. But this one was the most complicated so I thought I would explain it.

I am in no way saying that they will be faster or slower, just that they do not have any more or less grip.

Come at me.

Show me a 100kg 125GP champion. No? Why not?

[Matt Bleck]

2 alternative Nick Coles, in all respects the same but one is 110kg and the other is 90kg. 2 green Kawasakis both exactly the same except one is set up for 110kg Nick Cole and the other is set up for 90kg Nick Cole.
Who is going to lap faster?

Wouldn't the 90kg one would be classed as a "heavy" road racer?

[Shaun]

With the compression ratio you run you could have weighed 100kgs Dennis was only 50something kgs and even he still couldnt out gas you

you Protested you won and I got disqaulified eh, well done crasher. now go and tighten ya clip ons properlly. CBR cams checked officaually after manfield, GSXR cams and cases after Pukekohe, Boring dude, if it;s NOT prooven, it;s only rumour and Bull shit

[Moooools]

Show me a 100kg 125GP champion. No? Why not?

Facepalm.

Please read. I am not saying that a heavy rider can accelerate or brake as fast as a light rider, as there are limits on horsepower.

All I am saying is that a heavy rider and a light rider given infinite horsepower and braking power, would reach the limits of their tires at the same point.

I have said nothing about actual speed. Only about the limits of their tires which was brought up by the OP.

[Robert Taylor]

Wouldn't the 90kg one would be classed as a "heavy" road racer?

But of course.

[SWERVE]

Heres a more simple equation
T= Talent.
T - $ =
$ - T =
T + $ =

[Robert Taylor]

Facepalm.

Please read. I am not saying that a heavy rider can accelerate or brake as fast as a light rider, as there are limits on horsepower.

All I am saying is that a heavy rider and a light rider given infinite horsepower and braking power, would reach the limits of their tires at the same point.

I have said nothing about actual speed. Only about the limits of their tires which was brought up by the OP.

I hear what you are saying. Much of our work with road racing is managing rate of fore and aft weight transfer and how much pressure is placed on the tyres. A lighter rider will require in the first instance lighter springing. But also lighter valving. Its all about getting just the right amount of weight transfer to put enough pressure on the tyres to maximise mechanical grip between the tyre and the track. Of course myriad other factors also come into play, some of them contradictory
And then there are racing classes such as Formula Ford ( Praying Mantis's ) These cars dont have enough power to pull the skin off a rice pudding and often you deliberately take away some grip to stop ''scrubbing off '' too much speed.
Your third paragraph, while contestable does make some sense.